What is the answer to |x^2+3x-2|=2 ?

The answer to |x^2+3x-2|=2 is x=-4\lor x=-3\lor x=0\lor x=1

Solve for x: |x^2+3x-2|=2

The solution is x=-4\lor x=-3\lor x=0\lor x=1

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x^{2} + 3 x - 2 = 2

x = - 4 or x = - 3 or x = 0 or x = 1

Solution steps

x^{2} + 3 x - 2 = 2

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} + 3 x - 2 = - 2 or x^{2} + 3 x - 2 = 2

x^{2} + 3 x - 2 = - 2 or x^{2} + 3 x - 2 = 2

(x = - 3 or x = 0) or (x = - 4 or x = 1)

x = - 4 or x = - 3 or x = 0 or x = 1

\frac{1}{( \frac{1}{3} ) ^{2}}

r^{2} - 7 r + 6

9 y^{2} + 6 y - 8 = 0

x^{2} + 3 x = 24

\frac{15 d ^{- 9} t ^{4}}{( 5 d ^{- 3} t ) ^{- 2}}

What is the answer to |x^2+3x-2|=2 ?
The answer to |x^2+3x-2|=2 is x=-4\lor x=-3\lor x=0\lor x=1
Solve for x: |x^2+3x-2|=2
The solution is x=-4\lor x=-3\lor x=0\lor x=1