What are the solutions to the equation 121x^2-81=0 ?

The solutions to the equation 121x^2-81=0 are x= 9/11 ,x=-9/11

Find the zeros of 121x^2-81=0

The zeros of 121x^2-81=0 are x= 9/11 ,x=-9/11

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121 x^{2} - 81 = 0

x = \frac{9}{11}, x = - \frac{9}{11}

Decimal Notation

x = 0.81818 \dots, x = - 0.81818 \dots

Solution steps

121 x^{2} - 81 = 0

Move

81

to the right side

121 x^{2} = 81

Divide both sides by

121

x^{2} = \frac{81}{121}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{81}{121}, x = - \frac{81}{121}

\frac{81}{121} = \frac{9}{11}

- \frac{81}{121} = - \frac{9}{11}

x = \frac{9}{11}, x = - \frac{9}{11}

\frac{8}{π} (e - 1)

4 x^{2} + 36 x + 81

19 + 8 \leq 6 + 7 x

9 x^{\frac{4}{7}} - 1

2 x^{3} + 3 x^{2} - 14 x - 21

What are the solutions to the equation 121x^2-81=0 ?
The solutions to the equation 121x^2-81=0 are x= 9/11 ,x=-9/11
Find the zeros of 121x^2-81=0
The zeros of 121x^2-81=0 are x= 9/11 ,x=-9/11