What are the solutions to the equation x^2+18x+97=0 ?

The solutions to the equation x^2+18x+97=0 are x=-9+4i,x=-9-4i

Find the zeros of x^2+18x+97=0

The zeros of x^2+18x+97=0 are x=-9+4i,x=-9-4i

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x^{2} + 18 x + 97 = 0

x = - 9 + 4 i, x = - 9 - 4 i

Solution steps

x^{2} + 18 x + 97 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 97}{2 \cdot 1}

Simplify

1 8^{2} - 4 \cdot 1 \cdot 97 : 8 i

x_{1, 2} = \frac{- 18 \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 8 i}{2 \cdot 1}, x_{2} = \frac{- 18 - 8 i}{2 \cdot 1}

x = \frac{- 18 + 8 i}{2 \cdot 1} : - 9 + 4 i

x = \frac{- 18 - 8 i}{2 \cdot 1} : - 9 - 4 i

The solutions to the quadratic equation are:

x = - 9 + 4 i, x = - 9 - 4 i

- 2 = - (n - 8)

- 4 (- c - 8) = - 4 c - 8

\frac{x - 4}{x ^{2} - 64} > 0

x^{3} + 8 x^{2} + 16 x

5 x^{\frac{1}{2}} \cdot 2 x^{- \frac{5}{3}}

What are the solutions to the equation x^2+18x+97=0 ?
The solutions to the equation x^2+18x+97=0 are x=-9+4i,x=-9-4i
Find the zeros of x^2+18x+97=0
The zeros of x^2+18x+97=0 are x=-9+4i,x=-9-4i