What are the solutions to the equation 20x^2-39x-80=0 ?

The solutions to the equation 20x^2-39x-80=0 are x= 16/5 ,x=-5/4

Find the zeros of 20x^2-39x-80=0

The zeros of 20x^2-39x-80=0 are x= 16/5 ,x=-5/4

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20 x^{2} - 39 x - 80 = 0

x = \frac{16}{5}, x = - \frac{5}{4}

Decimal Notation

x = 3.2, x = - 1.25

Solution steps

20 x^{2} - 39 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 39 ) \pm ( - 39 ) ^{2} - 4 \cdot 20 ( - 80 )}{2 \cdot 20}

(- 39)^{2} - 4 \cdot 20 (- 80) = 89

x_{1, 2} = \frac{- ( - 39 ) \pm 89}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 39 ) + 89}{2 \cdot 20}, x_{2} = \frac{- ( - 39 ) - 89}{2 \cdot 20}

x = \frac{- ( - 39 ) + 89}{2 \cdot 20} : \frac{16}{5}

x = \frac{- ( - 39 ) - 89}{2 \cdot 20} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{16}{5}, x = - \frac{5}{4}

\frac{d - 2}{25} > \frac{d}{10} - \frac{1}{2}

x^{2} - 12 = 0

6 x^{2} = 17 x + 3

16 = x 2

(\frac{8}{3})^{1}

What are the solutions to the equation 20x^2-39x-80=0 ?
The solutions to the equation 20x^2-39x-80=0 are x= 16/5 ,x=-5/4
Find the zeros of 20x^2-39x-80=0
The zeros of 20x^2-39x-80=0 are x= 16/5 ,x=-5/4