What are the solutions to the equation u^2-3u+2=0 ?

The solutions to the equation u^2-3u+2=0 are u=2,u=1

Find the zeros of u^2-3u+2=0

The zeros of u^2-3u+2=0 are u=2,u=1

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u^{2} - 3 u + 2 = 0

u = 2, u = 1

Solution steps

u^{2} - 3 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

u_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, u_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

u = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

u = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

u = 2, u = 1

\frac{8}{2 - i}

x^{2} > 1

ln (2) = x

\frac{x + 1}{- x + 5} > 0

What are the solutions to the equation u^2-3u+2=0 ?
The solutions to the equation u^2-3u+2=0 are u=2,u=1
Find the zeros of u^2-3u+2=0
The zeros of u^2-3u+2=0 are u=2,u=1