What are the solutions to the equation 0=x^2+6x-7 ?

The solutions to the equation 0=x^2+6x-7 are x=1,x=-7

Find the zeros of 0=x^2+6x-7

The zeros of 0=x^2+6x-7 are x=1,x=-7

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0 = x^{2} + 6 x - 7

x = 1, x = - 7

Solution steps

0 = x^{2} + 6 x - 7

Switch sides

x^{2} + 6 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 7) = 8

x_{1, 2} = \frac{- 6 \pm 8}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 8}{2 \cdot 1}, x_{2} = \frac{- 6 - 8}{2 \cdot 1}

x = \frac{- 6 + 8}{2 \cdot 1} : 1

x = \frac{- 6 - 8}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = 1, x = - 7

d^{2} + d - 7 = - 5

\frac{1}{2} (2)

8 x - x^{2} = 15

1 5^{\frac{3}{2}}

166 = - 2 (- 5 + 2 x) - 9 x

What are the solutions to the equation 0=x^2+6x-7 ?
The solutions to the equation 0=x^2+6x-7 are x=1,x=-7
Find the zeros of 0=x^2+6x-7
The zeros of 0=x^2+6x-7 are x=1,x=-7