What is (2^0)/((2^{-2)x^{1/2}y^{-2})^3} ?

The solution to (2^0)/((2^{-2)x^{1/2}y^{-2})^3} is (64y^6)/(x^{3/2)}

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simplify (2^0)/((2^{-2)x^{1/2}y^{-2})^3}

simplify

\frac{2 ^{0}}{( 2 ^{- 2} x ^{\frac{1}{2}} y ^{- 2} ) ^{3}}

\frac{64 y ^{6}}{x ^{\frac{3}{2}}}

Solution steps

\frac{2 ^{0}}{( 2 ^{- 2} x ^{\frac{1}{2}} y ^{- 2} ) ^{3}}

Apply exponent rule:

a^{0} = 1, a \neq = 0

2^{0} = 1

= \frac{1}{( 2 ^{- 2} x ^{\frac{1}{2}} y ^{- 2} ) ^{3}}

Simplify

(2^{- 2} x^{\frac{1}{2}} y^{- 2})^{3} : \frac{x ^{\frac{3}{2}}}{64 y ^{6}}

= \frac{1}{\frac{x ^{\frac{3}{2}}}{64 y ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{64 y ^{6}}{x ^{\frac{3}{2}}}

\frac{\frac{2}{3}}{\frac{1}{5}}

- \frac{2}{3} - 1

x > 3 and x > 6

\frac{2 x - \frac{1}{2}}{4} = 3

(27)^{\frac{4}{3}}

What is (2^0)/((2^{-2)x^{1/2}y^{-2})^3} ?
The solution to (2^0)/((2^{-2)x^{1/2}y^{-2})^3} is (64y^6)/(x^{3/2)}