What is (x^2-10x+24)/(x^2-1)<= 0 ?

The solution to (x^2-10x+24)/(x^2-1)<= 0 is -1<x<1\lor 4<= x<= 6

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(x^2-10x+24)/(x^2-1)<= 0

\frac{x ^{2} - 10 x + 24}{x ^{2} - 1} \leq 0

- 1 < x < 1 or 4 \leq x \leq 6

Interval Notation

(- 1, 1) \cup [4, 6]

Solution steps

\frac{x ^{2} - 10 x + 24}{x ^{2} - 1} \leq 0

Factor

\frac{x ^{2} - 10 x + 24}{x ^{2} - 1} : \frac{( x - 4 ) ( x - 6 )}{( x + 1 ) ( x - 1 )}

\frac{( x - 4 ) ( x - 6 )}{( x + 1 ) ( x - 1 )} \leq 0

Identify the intervals

- 1 < x < 1 or 4 \leq x \leq 6

\frac{3}{3 + 2}

2 x^{2} - 10 x + 15 \geq 3

1 - \frac{1}{2} - \frac{1}{3}

\frac{14 !}{11 !}

(\frac{1}{4} + \frac{5}{4})^{2} + \frac{3}{4}

What is (x^2-10x+24)/(x^2-1)<= 0 ?
The solution to (x^2-10x+24)/(x^2-1)<= 0 is -1<x<1\lor 4<= x<= 6