What are the solutions to the equation 8^2+4^2=x^2 ?

The solutions to the equation 8^2+4^2=x^2 are x=4sqrt(5),x=-4sqrt(5)

Find the zeros of 8^2+4^2=x^2

The zeros of 8^2+4^2=x^2 are x=4sqrt(5),x=-4sqrt(5)

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8^{2} + 4^{2} = x^{2}

x = 45, x = - 45

Decimal Notation

x = 8.94427 \dots, x = - 8.94427 \dots

Solution steps

8^{2} + 4^{2} = x^{2}

Switch sides

x^{2} = 8^{2} + 4^{2}

Simplify

8^{2} + 4^{2} : 80

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 80, x = - 80

80 = 45

- 80 = - 45

x = 45, x = - 45

x^{2} + 3 x = 10

- 11 w > - 11

21 a + 8 x y^{3} - 24 y^{2} - 7 a x y

(\frac{1}{2} x^{2} y^{3})^{4} (4 x^{5} y^{3})^{2}

5 y - \frac{3}{5} = \frac{4}{5}

What are the solutions to the equation 8^2+4^2=x^2 ?
The solutions to the equation 8^2+4^2=x^2 are x=4sqrt(5),x=-4sqrt(5)
Find the zeros of 8^2+4^2=x^2
The zeros of 8^2+4^2=x^2 are x=4sqrt(5),x=-4sqrt(5)