What are the solutions to the equation 4q^2+16q-9=0 ?

The solutions to the equation 4q^2+16q-9=0 are q= 1/2 ,q=-9/2

Find the zeros of 4q^2+16q-9=0

The zeros of 4q^2+16q-9=0 are q= 1/2 ,q=-9/2

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4 q^{2} + 16 q - 9 = 0

q = \frac{1}{2}, q = - \frac{9}{2}

Solution steps

4 q^{2} + 16 q - 9 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 (- 9) = 20

q_{1, 2} = \frac{- 16 \pm 20}{2 \cdot 4}

Separate the solutions

q_{1} = \frac{- 16 + 20}{2 \cdot 4}, q_{2} = \frac{- 16 - 20}{2 \cdot 4}

q = \frac{- 16 + 20}{2 \cdot 4} : \frac{1}{2}

q = \frac{- 16 - 20}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

q = \frac{1}{2}, q = - \frac{9}{2}

(8)^{\frac{2}{3}}

(\frac{1}{5})^{1}

4 - 5 (\frac{3}{4})

40 x y + 8 x - 15 y - 3

\frac{p ( x )}{q ( x )}

What are the solutions to the equation 4q^2+16q-9=0 ?
The solutions to the equation 4q^2+16q-9=0 are q= 1/2 ,q=-9/2
Find the zeros of 4q^2+16q-9=0
The zeros of 4q^2+16q-9=0 are q= 1/2 ,q=-9/2