What are the solutions to the equation m^2-2/3 m= 1/3 ?

The solutions to the equation m^2-2/3 m= 1/3 are m=1,m=-1/3

Find the zeros of m^2-2/3 m= 1/3

The zeros of m^2-2/3 m= 1/3 are m=1,m=-1/3

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m^{2} - \frac{2}{3} m = \frac{1}{3}

m = 1, m = - \frac{1}{3}

Decimal Notation

m = 1, m = - 0.33333 \dots

Solution steps

m^{2} - \frac{2}{3} m = \frac{1}{3}

Multiply both sides by

3

3 m^{2} - 2 m = 1

Move

1

to the left side

3 m^{2} - 2 m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 1 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 1) = 4

m_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 3}, m_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 3}

m = \frac{- ( - 2 ) + 4}{2 \cdot 3} : 1

m = \frac{- ( - 2 ) - 4}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

m = 1, m = - \frac{1}{3}

- 25 t^{2} + 200 t + 375 = 0

2 x + x = 0

\frac{7}{10} \cdot \frac{2}{3}

\frac{5 x - 12}{- 4} = - 7

\frac{r}{3} + 5 \leq 8

What are the solutions to the equation m^2-2/3 m= 1/3 ?
The solutions to the equation m^2-2/3 m= 1/3 are m=1,m=-1/3
Find the zeros of m^2-2/3 m= 1/3
The zeros of m^2-2/3 m= 1/3 are m=1,m=-1/3