What are the solutions to the equation a^2+7a=120 ?

The solutions to the equation a^2+7a=120 are a=8,a=-15

Find the zeros of a^2+7a=120

The zeros of a^2+7a=120 are a=8,a=-15

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a^{2} + 7 a = 120

a = 8, a = - 15

Solution steps

a^{2} + 7 a = 120

Move

120

to the left side

a^{2} + 7 a - 120 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot ( - 120 )}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot (- 120) = 23

a_{1, 2} = \frac{- 7 \pm 23}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 7 + 23}{2 \cdot 1}, a_{2} = \frac{- 7 - 23}{2 \cdot 1}

a = \frac{- 7 + 23}{2 \cdot 1} : 8

a = \frac{- 7 - 23}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

a = 8, a = - 15

3 x^{2} + x + 2 = 0

5 x^{2} - 20 x + 20

\frac{1}{8} (2 x + 4) > \frac{1}{4} (2 x + 8) + 1

48 n^{3} + 9 n - 3 n

\frac{9}{6} = \frac{x}{10}

What are the solutions to the equation a^2+7a=120 ?
The solutions to the equation a^2+7a=120 are a=8,a=-15
Find the zeros of a^2+7a=120
The zeros of a^2+7a=120 are a=8,a=-15