What are the solutions to the equation a^2+3^2=7^2 ?

The solutions to the equation a^2+3^2=7^2 are a=2sqrt(10),a=-2sqrt(10)

Find the zeros of a^2+3^2=7^2

The zeros of a^2+3^2=7^2 are a=2sqrt(10),a=-2sqrt(10)

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a^{2} + 3^{2} = 7^{2}

a = 210, a = - 210

Decimal Notation

a = 6.32455 \dots, a = - 6.32455 \dots

Solution steps

a^{2} + 3^{2} = 7^{2}

Move

3^{2}

to the right side

a^{2} = 40

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 40, a = - 40

40 = 210

- 40 = - 210

a = 210, a = - 210

2 v^{2} - 33 v + 16

π - \frac{2 π}{3}

\frac{x ^{2} ( 3 - x )}{x + 2} \leq 0

x^{2} - 32 x + 31

2 (x - 4) < x + 7

What are the solutions to the equation a^2+3^2=7^2 ?
The solutions to the equation a^2+3^2=7^2 are a=2sqrt(10),a=-2sqrt(10)
Find the zeros of a^2+3^2=7^2
The zeros of a^2+3^2=7^2 are a=2sqrt(10),a=-2sqrt(10)