What are the solutions to the equation 0=x^2+6x+4 ?

The solutions to the equation 0=x^2+6x+4 are x=-3+sqrt(5),x=-3-sqrt(5)

Find the zeros of 0=x^2+6x+4

The zeros of 0=x^2+6x+4 are x=-3+sqrt(5),x=-3-sqrt(5)

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0 = x^{2} + 6 x + 4

x = - 3 + 5, x = - 3 - 5

Decimal Notation

x = - 0.76393 \dots, x = - 5.23606 \dots

Solution steps

0 = x^{2} + 6 x + 4

Switch sides

x^{2} + 6 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 4 = 25

x_{1, 2} = \frac{- 6 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 5}{2 \cdot 1}

x = \frac{- 6 + 2 5}{2 \cdot 1} : - 3 + 5

x = \frac{- 6 - 2 5}{2 \cdot 1} : - 3 - 5

The solutions to the quadratic equation are:

x = - 3 + 5, x = - 3 - 5

7 w - 3 (4 w + 8) = 11

8 x^{- 2}

\frac{3}{4} x - 2 x \leq 1 + 2

4 {x - (3 x - 2)} > 3 (x + 5) - 15

8 x^{2} + 21 = - 59 x

What are the solutions to the equation 0=x^2+6x+4 ?
The solutions to the equation 0=x^2+6x+4 are x=-3+sqrt(5),x=-3-sqrt(5)
Find the zeros of 0=x^2+6x+4
The zeros of 0=x^2+6x+4 are x=-3+sqrt(5),x=-3-sqrt(5)