What are the solutions to the equation x^2=12-x ?

The solutions to the equation x^2=12-x are x=3,x=-4

Find the zeros of x^2=12-x

The zeros of x^2=12-x are x=3,x=-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = 12 - x

x = 3, x = - 4

Solution steps

x^{2} = 12 - x

Move

x

to the left side

x^{2} + x = 12

Move

12

to the left side

x^{2} + x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 12) = 7

x_{1, 2} = \frac{- 1 \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 7}{2 \cdot 1}, x_{2} = \frac{- 1 - 7}{2 \cdot 1}

x = \frac{- 1 + 7}{2 \cdot 1} : 3

x = \frac{- 1 - 7}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

\frac{14 x ^{8} y ^{7}}{7 x y ^{8}}

2 \cdot \frac{4}{3}

\frac{1}{16} + \frac{1}{3}

3 \leq x

\frac{11 π}{6} \cdot \frac{180}{π}

What are the solutions to the equation x^2=12-x ?
The solutions to the equation x^2=12-x are x=3,x=-4
Find the zeros of x^2=12-x
The zeros of x^2=12-x are x=3,x=-4