What is 2x^2-11x-16<= 5 ?

The solution to 2x^2-11x-16<= 5 is -3/2 <= x<= 7

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2x^2-11x-16<= 5

2 x^{2} - 11 x - 16 \leq 5

- \frac{3}{2} \leq x \leq 7

Interval Notation

[- \frac{3}{2}, 7]

Decimal Notation

- 1.5 \leq x \leq 7

Solution steps

2 x^{2} - 11 x - 16 \leq 5

Rewrite in standard form

2 x^{2} - 11 x - 21 \leq 0

Factor

2 x^{2} - 11 x - 21 : (2 x + 3) (x - 7)

(2 x + 3) (x - 7) \leq 0

Identify the intervals

- \frac{3}{2} \leq x \leq 7

x^{- 3} y^{\frac{1}{3}} x^{- 2} y^{- \frac{1}{2}}

\frac{8}{6}

\frac{x ( x - 5 )}{x + 3} > 0

\frac{2 ( 3 )}{3 + 1}

6 x^{2} - 24 x + 18