en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

log_{2}(3x+1)<= 4

Solution

lo g_{2} (3 x + 1) \leq 4

Solution

- \frac{1}{3} < x \leq 5

+2

Solution steps

lo g_{2} (3 x + 1) \leq 4

Apply log rules

3 x + 1 \leq 16 and 3 x + 1 > 0

3 x + 1 \leq 16 and 3 x + 1 > 0 : - \frac{1}{3} < x \leq 5

- \frac{1}{3} < x \leq 5

Popular Examples

simplify (3+i)/(4+i)simplify

\frac{3 + i}{4 + i}

u^{2} = 36

8 x - 5 = 5 x + 7

1+9(x-1)<7+9(x+1)\land 7x-3<= 18

1 + 9 (x - 1) < 7 + 9 (x + 1) and 7 x - 3 \leq 18

simplify (7i)/(4+i)simplify

\frac{7 i}{4 + i}

Frequently Asked Questions (FAQ)

What is log_{2}(3x+1)<= 4 ?
The solution to log_{2}(3x+1)<= 4 is -1/3 <x<= 5