What are the solutions to the equation r^2+10r+25=0 ?

The solutions to the equation r^2+10r+25=0 are r=-5

Find the zeros of r^2+10r+25=0

The zeros of r^2+10r+25=0 are r=-5

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r^{2} + 10 r + 25 = 0

r = - 5

Solution steps

r^{2} + 10 r + 25 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

r_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

r = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

r = - 5

The solution to the quadratic equation is:

r = - 5

- (4)^{3}

(1 + \frac{0.01}{2})^{2} - 1

∣ 6 - 4 x ∣ \leq 3

8 s^{2} - 44 s + 60 = 0

- 7 = \frac{5}{7} n + 23

What are the solutions to the equation r^2+10r+25=0 ?
The solutions to the equation r^2+10r+25=0 are r=-5
Find the zeros of r^2+10r+25=0
The zeros of r^2+10r+25=0 are r=-5