What is the answer to 3y+4(y+3)-5(1-2y)=1-4(5y-2)-4y-1 ?

The answer to 3y+4(y+3)-5(1-2y)=1-4(5y-2)-4y-1 is y= 1/41

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3y+4(y+3)-5(1-2y)=1-4(5y-2)-4y-1

3 y + 4 (y + 3) - 5 (1 - 2 y) = 1 - 4 (5 y - 2) - 4 y - 1

y = \frac{1}{41}

Decimal Notation

y = 0.02439 \dots

Solution steps

3 y + 4 (y + 3) - 5 (1 - 2 y) = 1 - 4 (5 y - 2) - 4 y - 1

Group like terms

3 y + 4 (y + 3) - 5 (1 - 2 y) = - 4 y - 4 (5 y - 2) + 1 - 1

1 - 1 = 0

3 y + 4 (y + 3) - 5 (1 - 2 y) = - 4 y - 4 (5 y - 2)

Expand

- 4 (5 y - 2) : - 20 y + 8

17 y + 7 = - 4 y - 20 y + 8

Add similar elements:

- 4 y - 20 y = - 24 y

17 y + 7 = - 24 y + 8

Expand

3 y + 4 (y + 3) - 5 (1 - 2 y) : 17 y + 7

17 y + 7 = - 24 y + 8

Move

7

to the right side

17 y = - 24 y + 1

Move

24 y

to the left side

41 y = 1

Divide both sides by

41

y = \frac{1}{41}

98 - 2 y^{4}

15 - 4 x \geq \frac{10 x + 1}{3}

28 - 63

12 x^{2} + 10 x - 12

\frac{y}{4} - 1 > 1

What is the answer to 3y+4(y+3)-5(1-2y)=1-4(5y-2)-4y-1 ?
The answer to 3y+4(y+3)-5(1-2y)=1-4(5y-2)-4y-1 is y= 1/41
Solve for y: 3y+4(y+3)-5(1-2y)=1-4(5y-2)-4y-1
The solution is y= 1/41