What are the solutions to the equation 4x^2+x-1=0 ?

The solutions to the equation 4x^2+x-1=0 are x=(-1+sqrt(17))/8 ,x=(-1-sqrt(17))/8

Find the zeros of 4x^2+x-1=0

The zeros of 4x^2+x-1=0 are x=(-1+sqrt(17))/8 ,x=(-1-sqrt(17))/8

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4 x^{2} + x - 1 = 0

x = \frac{- 1 + 17}{8}, x = \frac{- 1 - 17}{8}

Decimal Notation

x = 0.39038 \dots, x = - 0.64038 \dots

Solution steps

4 x^{2} + x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 1) = 17

x_{1, 2} = \frac{- 1 \pm 17}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 17}{2 \cdot 4}, x_{2} = \frac{- 1 - 17}{2 \cdot 4}

x = \frac{- 1 + 17}{2 \cdot 4} : \frac{- 1 + 17}{8}

x = \frac{- 1 - 17}{2 \cdot 4} : \frac{- 1 - 17}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 17}{8}, x = \frac{- 1 - 17}{8}

\frac{5}{27} + \frac{1}{6}

\frac{2}{5} + \frac{4}{7}

5 x^{2} + 15 x + 10

m - 6 < 1

1 - r^{3}

What are the solutions to the equation 4x^2+x-1=0 ?
The solutions to the equation 4x^2+x-1=0 are x=(-1+sqrt(17))/8 ,x=(-1-sqrt(17))/8
Find the zeros of 4x^2+x-1=0
The zeros of 4x^2+x-1=0 are x=(-1+sqrt(17))/8 ,x=(-1-sqrt(17))/8