What are the solutions to the equation 2+(y-7)^2=18 ?

The solutions to the equation 2+(y-7)^2=18 are y=11,y=3

Find the zeros of 2+(y-7)^2=18

The zeros of 2+(y-7)^2=18 are y=11,y=3

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2 + (y - 7)^{2} = 18

y = 11, y = 3

Solution steps

2 + (y - 7)^{2} = 18

Move

2

to the right side

(y - 7)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 7 = 16 : y = 11

Solve

y - 7 = - 16 : y = 3

The solutions to the quadratic equation are:

y = 11, y = 3

\frac{7}{2} \cdot \frac{9}{4}

(1 - 2 x)^{2} - 8 = 0

x^{2} - 8 x = 9 x

\frac{2 x}{5} = \frac{x + 4}{3}

1 + 2 x + x^{2} = 0

What are the solutions to the equation 2+(y-7)^2=18 ?
The solutions to the equation 2+(y-7)^2=18 are y=11,y=3
Find the zeros of 2+(y-7)^2=18
The zeros of 2+(y-7)^2=18 are y=11,y=3