What are the solutions to the equation 5x^2+50x=-125 ?

The solutions to the equation 5x^2+50x=-125 are x=-5

Find the zeros of 5x^2+50x=-125

The zeros of 5x^2+50x=-125 are x=-5

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5 x^{2} + 50 x = - 125

x = - 5

Solution steps

5 x^{2} + 50 x = - 125

Move

125

to the left side

5 x^{2} + 50 x + 125 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 5 \cdot 125}{2 \cdot 5}

5 0^{2} - 4 \cdot 5 \cdot 125 = 0

x_{1, 2} = \frac{- 50 \pm 0}{2 \cdot 5}

x = \frac{- 50}{2 \cdot 5}

\frac{- 50}{2 \cdot 5} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

X - 12 = 14

1 + \frac{0.25}{100}

x^{2} - 7 x + 12 = 0

- \frac{3}{4} + 1

3 x^{2} \leq 27

What are the solutions to the equation 5x^2+50x=-125 ?
The solutions to the equation 5x^2+50x=-125 are x=-5
Find the zeros of 5x^2+50x=-125
The zeros of 5x^2+50x=-125 are x=-5