What are the solutions to the equation 49x^2+140x+100=0 ?

The solutions to the equation 49x^2+140x+100=0 are x=-10/7

Find the zeros of 49x^2+140x+100=0

The zeros of 49x^2+140x+100=0 are x=-10/7

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49 x^{2} + 140 x + 100 = 0

x = - \frac{10}{7}

Decimal Notation

x = - 1.42857 \dots

Solution steps

49 x^{2} + 140 x + 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 140 \pm 14 0 ^{2} - 4 \cdot 49 \cdot 100}{2 \cdot 49}

14 0^{2} - 4 \cdot 49 \cdot 100 = 0

x_{1, 2} = \frac{- 140 \pm 0}{2 \cdot 49}

x = \frac{- 140}{2 \cdot 49}

\frac{- 140}{2 \cdot 49} = - \frac{10}{7}

x = - \frac{10}{7}

The solution to the quadratic equation is:

x = - \frac{10}{7}

10 x^{2} y - 15 x y^{2}

x^{3} + 8 x^{2} + 7 x

5 x - 17 + 3 x + 9 + x + 17 = 180

- v + 5 + 6 v = 1 + 5 v + 3

lo g_{9} (243) = x

What are the solutions to the equation 49x^2+140x+100=0 ?
The solutions to the equation 49x^2+140x+100=0 are x=-10/7
Find the zeros of 49x^2+140x+100=0
The zeros of 49x^2+140x+100=0 are x=-10/7