What are the solutions to the equation (x+2)(x+2)=0 ?

The solutions to the equation (x+2)(x+2)=0 are x=-2

Find the zeros of (x+2)(x+2)=0

The zeros of (x+2)(x+2)=0 are x=-2

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(x + 2) (x + 2) = 0

x = - 2

Solution steps

(x + 2) (x + 2) = 0

Simplify

(x + 2)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

x + 2 = 0 : x = - 2

The solution to the quadratic equation is:

x = - 2

5 b^{2} + 21 b + 4

9^{\frac{5}{2}}

(f^{- 3} g^{5} h^{8})^{- 3}

\frac{( - 6 ) - 4}{( - 6 ) ^{2} - 16}

10 h + 12 = 8 h + 4

What are the solutions to the equation (x+2)(x+2)=0 ?
The solutions to the equation (x+2)(x+2)=0 are x=-2
Find the zeros of (x+2)(x+2)=0
The zeros of (x+2)(x+2)=0 are x=-2