What are the solutions to the equation 10x^2+6x+1=0 ?

The solutions to the equation 10x^2+6x+1=0 are x=-3/10+i 1/10 ,x=-3/10-i 1/10

Find the zeros of 10x^2+6x+1=0

The zeros of 10x^2+6x+1=0 are x=-3/10+i 1/10 ,x=-3/10-i 1/10

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10 x^{2} + 6 x + 1 = 0

x = - \frac{3}{10} + i \frac{1}{10}, x = - \frac{3}{10} - i \frac{1}{10}

Solution steps

10 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 10 \cdot 1}{2 \cdot 10}

Simplify

6^{2} - 4 \cdot 10 \cdot 1 : 2 i

x_{1, 2} = \frac{- 6 \pm 2 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 6 + 2 i}{2 \cdot 10}, x_{2} = \frac{- 6 - 2 i}{2 \cdot 10}

x = \frac{- 6 + 2 i}{2 \cdot 10} : - \frac{3}{10} + i \frac{1}{10}

x = \frac{- 6 - 2 i}{2 \cdot 10} : - \frac{3}{10} - i \frac{1}{10}

The solutions to the quadratic equation are:

x = - \frac{3}{10} + i \frac{1}{10}, x = - \frac{3}{10} - i \frac{1}{10}

- 4 m + 21 (m - 1) \leq 15 m + 2 (m - 1)

0 \geq \frac{5 - x}{2} \geq - 10

\frac{( n + 2 ) !}{( n + 1 ) !}

(- 1)^{\frac{4}{5}}

32 e^{2} - 50

What are the solutions to the equation 10x^2+6x+1=0 ?
The solutions to the equation 10x^2+6x+1=0 are x=-3/10+i 1/10 ,x=-3/10-i 1/10
Find the zeros of 10x^2+6x+1=0
The zeros of 10x^2+6x+1=0 are x=-3/10+i 1/10 ,x=-3/10-i 1/10