What are the solutions to the equation x^2+17x+49=0 ?

The solutions to the equation x^2+17x+49=0 are x=(-17+sqrt(93))/2 ,x=(-17-sqrt(93))/2

Find the zeros of x^2+17x+49=0

The zeros of x^2+17x+49=0 are x=(-17+sqrt(93))/2 ,x=(-17-sqrt(93))/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 17 x + 49 = 0

x = \frac{- 17 + 93}{2}, x = \frac{- 17 - 93}{2}

Decimal Notation

x = - 3.67817 \dots, x = - 13.32182 \dots

Solution steps

x^{2} + 17 x + 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 17 \pm 1 7 ^{2} - 4 \cdot 1 \cdot 49}{2 \cdot 1}

1 7^{2} - 4 \cdot 1 \cdot 49 = 93

x_{1, 2} = \frac{- 17 \pm 93}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 17 + 93}{2 \cdot 1}, x_{2} = \frac{- 17 - 93}{2 \cdot 1}

x = \frac{- 17 + 93}{2 \cdot 1} : \frac{- 17 + 93}{2}

x = \frac{- 17 - 93}{2 \cdot 1} : \frac{- 17 - 93}{2}

The solutions to the quadratic equation are:

x = \frac{- 17 + 93}{2}, x = \frac{- 17 - 93}{2}

\frac{2 π}{1}

∣ x - 8 ∣ = 5

a^{2} - 4 ab + 3 b^{2}

4 x^{2} - 7 x - 2

\frac{4 ^{9}}{4 ^{7}}

What are the solutions to the equation x^2+17x+49=0 ?
The solutions to the equation x^2+17x+49=0 are x=(-17+sqrt(93))/2 ,x=(-17-sqrt(93))/2
Find the zeros of x^2+17x+49=0
The zeros of x^2+17x+49=0 are x=(-17+sqrt(93))/2 ,x=(-17-sqrt(93))/2