What are the solutions to the equation 4x^2-x+1=0 ?

The solutions to the equation 4x^2-x+1=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8

Find the zeros of 4x^2-x+1=0

The zeros of 4x^2-x+1=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8

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4 x^{2} - x + 1 = 0

x = \frac{1}{8} + i \frac{15}{8}, x = \frac{1}{8} - i \frac{15}{8}

Solution steps

4 x^{2} - x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

Simplify

(- 1)^{2} - 4 \cdot 4 \cdot 1 : 15 i

x_{1, 2} = \frac{- ( - 1 ) \pm 15 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 15 i}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 15 i}{2 \cdot 4}

x = \frac{- ( - 1 ) + 15 i}{2 \cdot 4} : \frac{1}{8} + i \frac{15}{8}

x = \frac{- ( - 1 ) - 15 i}{2 \cdot 4} : \frac{1}{8} - i \frac{15}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{15}{8}, x = \frac{1}{8} - i \frac{15}{8}

\frac{2 + 3 i}{1 - i}

3 a^{2} + 16 a - 12

\frac{5}{3 x + 1} - \frac{20}{9 x ^{2} - 1} \leq \frac{2}{3 x - 1}

72 + 4 - 14 d = 36

- 2 \leq \frac{\frac{1}{x + 4} - \frac{1}{4}}{x} \leq x + 3

What are the solutions to the equation 4x^2-x+1=0 ?
The solutions to the equation 4x^2-x+1=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8
Find the zeros of 4x^2-x+1=0
The zeros of 4x^2-x+1=0 are x= 1/8+i(sqrt(15))/8 ,x= 1/8-i(sqrt(15))/8