What are the solutions to the equation 3x^2+12x+6=0 ?

The solutions to the equation 3x^2+12x+6=0 are x=-2+sqrt(2),x=-2-sqrt(2)

Find the zeros of 3x^2+12x+6=0

The zeros of 3x^2+12x+6=0 are x=-2+sqrt(2),x=-2-sqrt(2)

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3 x^{2} + 12 x + 6 = 0

x = - 2 + 2, x = - 2 - 2

Decimal Notation

x = - 0.58578 \dots, x = - 3.41421 \dots

Solution steps

3 x^{2} + 12 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 \cdot 6}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 \cdot 6 = 62

x_{1, 2} = \frac{- 12 \pm 6 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 6 2}{2 \cdot 3}, x_{2} = \frac{- 12 - 6 2}{2 \cdot 3}

x = \frac{- 12 + 6 2}{2 \cdot 3} : - 2 + 2

x = \frac{- 12 - 6 2}{2 \cdot 3} : - 2 - 2

The solutions to the quadratic equation are:

x = - 2 + 2, x = - 2 - 2

a^{3} + 125

\frac{3 x - 3}{5} + \frac{x + 3}{3} = 6

3 (x - 3) = - 15

2 x^{2} + 20 x + 57 = 4

5 x - 4 = x + 3

What are the solutions to the equation 3x^2+12x+6=0 ?
The solutions to the equation 3x^2+12x+6=0 are x=-2+sqrt(2),x=-2-sqrt(2)
Find the zeros of 3x^2+12x+6=0
The zeros of 3x^2+12x+6=0 are x=-2+sqrt(2),x=-2-sqrt(2)