What are the solutions to the equation 6x^2-49x+8=0 ?

The solutions to the equation 6x^2-49x+8=0 are x=8,x= 1/6

Find the zeros of 6x^2-49x+8=0

The zeros of 6x^2-49x+8=0 are x=8,x= 1/6

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6 x^{2} - 49 x + 8 = 0

x = 8, x = \frac{1}{6}

Decimal Notation

x = 8, x = 0.16666 \dots

Solution steps

6 x^{2} - 49 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 49 ) \pm ( - 49 ) ^{2} - 4 \cdot 6 \cdot 8}{2 \cdot 6}

(- 49)^{2} - 4 \cdot 6 \cdot 8 = 47

x_{1, 2} = \frac{- ( - 49 ) \pm 47}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 49 ) + 47}{2 \cdot 6}, x_{2} = \frac{- ( - 49 ) - 47}{2 \cdot 6}

x = \frac{- ( - 49 ) + 47}{2 \cdot 6} : 8

x = \frac{- ( - 49 ) - 47}{2 \cdot 6} : \frac{1}{6}

The solutions to the quadratic equation are:

x = 8, x = \frac{1}{6}

(- 3 \cdot 1 0^{3}) \cdot (4 \cdot 1 0^{6})

(x - 2) (x + 1) < 0

2 x^{2} - 6 x - 20

r^{2} + 6 r - 7 = 0

- 10 = - 2 + \frac{1}{2} d

What are the solutions to the equation 6x^2-49x+8=0 ?
The solutions to the equation 6x^2-49x+8=0 are x=8,x= 1/6
Find the zeros of 6x^2-49x+8=0
The zeros of 6x^2-49x+8=0 are x=8,x= 1/6