What are the solutions to the equation 5x^2-19x=4 ?

The solutions to the equation 5x^2-19x=4 are x=4,x=-1/5

Find the zeros of 5x^2-19x=4

The zeros of 5x^2-19x=4 are x=4,x=-1/5

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5 x^{2} - 19 x = 4

x = 4, x = - \frac{1}{5}

Decimal Notation

x = 4, x = - 0.2

Solution steps

5 x^{2} - 19 x = 4

Move

4

to the left side

5 x^{2} - 19 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 5 ( - 4 )}{2 \cdot 5}

(- 19)^{2} - 4 \cdot 5 (- 4) = 21

x_{1, 2} = \frac{- ( - 19 ) \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 21}{2 \cdot 5}, x_{2} = \frac{- ( - 19 ) - 21}{2 \cdot 5}

x = \frac{- ( - 19 ) + 21}{2 \cdot 5} : 4

x = \frac{- ( - 19 ) - 21}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 4, x = - \frac{1}{5}

ln (2) + ln (5)

i^{1}

4 x^{2} - 25 y^{2}

2 x^{2} - 25 x + 12

- \frac{9}{4} + 2

What are the solutions to the equation 5x^2-19x=4 ?
The solutions to the equation 5x^2-19x=4 are x=4,x=-1/5
Find the zeros of 5x^2-19x=4
The zeros of 5x^2-19x=4 are x=4,x=-1/5