What are the solutions to the equation x^2-2x+20=0 ?

The solutions to the equation x^2-2x+20=0 are x=1+sqrt(19)i,x=1-sqrt(19)i

Find the zeros of x^2-2x+20=0

The zeros of x^2-2x+20=0 are x=1+sqrt(19)i,x=1-sqrt(19)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 2 x + 20 = 0

x = 1 + 19 i, x = 1 - 19 i

Solution steps

x^{2} - 2 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 20 : 219 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 19 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 19 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 19 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 19 i}{2 \cdot 1} : 1 + 19 i

x = \frac{- ( - 2 ) - 2 19 i}{2 \cdot 1} : 1 - 19 i

The solutions to the quadratic equation are:

x = 1 + 19 i, x = 1 - 19 i

4 x^{2} + 44 x + 112

x^{2} + x - 6 < 3

- 35 y^{4} x^{3} - 30 y^{3} + 50 y^{2}

(\frac{16}{3})^{14}

\frac{3}{5} + 4

What are the solutions to the equation x^2-2x+20=0 ?
The solutions to the equation x^2-2x+20=0 are x=1+sqrt(19)i,x=1-sqrt(19)i
Find the zeros of x^2-2x+20=0
The zeros of x^2-2x+20=0 are x=1+sqrt(19)i,x=1-sqrt(19)i