What are the solutions to the equation (2x-9)^2=12 ?

The solutions to the equation (2x-9)^2=12 are x=(2sqrt(3)+9)/2 ,x=(-2sqrt(3)+9)/2

Find the zeros of (2x-9)^2=12

The zeros of (2x-9)^2=12 are x=(2sqrt(3)+9)/2 ,x=(-2sqrt(3)+9)/2

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(2 x - 9)^{2} = 12

x = \frac{2 3 + 9}{2}, x = \frac{- 2 3 + 9}{2}

Decimal Notation

x = 6.23205 \dots, x = 2.76794 \dots

Solution steps

(2 x - 9)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 9 = 12 : x = \frac{2 3 + 9}{2}

Solve

2 x - 9 = - 12 : x = \frac{- 2 3 + 9}{2}

The solutions to the quadratic equation are:

x = \frac{2 3 + 9}{2}, x = \frac{- 2 3 + 9}{2}

- \frac{1}{5} p + \frac{9}{5} p + 6 = 30

2180

4 a^{4} b - 6 a^{2} b^{2} + 12 a^{3} b

2 \cdot 0.6

7 x^{2} + 4 x = 2

What are the solutions to the equation (2x-9)^2=12 ?
The solutions to the equation (2x-9)^2=12 are x=(2sqrt(3)+9)/2 ,x=(-2sqrt(3)+9)/2
Find the zeros of (2x-9)^2=12
The zeros of (2x-9)^2=12 are x=(2sqrt(3)+9)/2 ,x=(-2sqrt(3)+9)/2