What are the solutions to the equation (x+1)(x-10)=0 ?

The solutions to the equation (x+1)(x-10)=0 are x=-1,x=10

Find the zeros of (x+1)(x-10)=0

The zeros of (x+1)(x-10)=0 are x=-1,x=10

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(x + 1) (x - 10) = 0

x = - 1, x = 10

Solution steps

(x + 1) (x - 10) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x - 10 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x - 10 = 0 : x = 10

The solutions to the quadratic equation are:

x = - 1, x = 10

8 - \frac{3 x}{10} + \frac{2 x}{4} - \frac{5 x}{8} = - 9

4 x - \frac{2}{5} > \frac{3}{5}

19 - 2 (1 - x) < 13

3 x^{2} - 7 x + 9 = 0

\frac{1}{4} \cdot \frac{1}{8}

What are the solutions to the equation (x+1)(x-10)=0 ?
The solutions to the equation (x+1)(x-10)=0 are x=-1,x=10
Find the zeros of (x+1)(x-10)=0
The zeros of (x+1)(x-10)=0 are x=-1,x=10