What are the solutions to the equation 0=x^2-10x+21 ?

The solutions to the equation 0=x^2-10x+21 are x=7,x=3

Find the zeros of 0=x^2-10x+21

The zeros of 0=x^2-10x+21 are x=7,x=3

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0 = x^{2} - 10 x + 21

x = 7, x = 3

Solution steps

0 = x^{2} - 10 x + 21

Switch sides

x^{2} - 10 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

x_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

x = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 7, x = 3

16 + s \leq - 80

\frac{e ^{x}}{e ^{x}}

- \frac{5}{6} + 1

2 (p^{\frac{2}{3}} q^{\frac{1}{3}})^{- \frac{3}{4}}

What are the solutions to the equation 0=x^2-10x+21 ?
The solutions to the equation 0=x^2-10x+21 are x=7,x=3
Find the zeros of 0=x^2-10x+21
The zeros of 0=x^2-10x+21 are x=7,x=3