What are the solutions to the equation 4x^2-12x=7 ?

The solutions to the equation 4x^2-12x=7 are x= 7/2 ,x=-1/2

Find the zeros of 4x^2-12x=7

The zeros of 4x^2-12x=7 are x= 7/2 ,x=-1/2

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4 x^{2} - 12 x = 7

x = \frac{7}{2}, x = - \frac{1}{2}

Decimal Notation

x = 3.5, x = - 0.5

Solution steps

4 x^{2} - 12 x = 7

Move

7

to the left side

4 x^{2} - 12 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 ( - 7 )}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 (- 7) = 16

x_{1, 2} = \frac{- ( - 12 ) \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 16}{2 \cdot 4}, x_{2} = \frac{- ( - 12 ) - 16}{2 \cdot 4}

x = \frac{- ( - 12 ) + 16}{2 \cdot 4} : \frac{7}{2}

x = \frac{- ( - 12 ) - 16}{2 \cdot 4} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{7}{2}, x = - \frac{1}{2}

\frac{8}{2} \cdot 3

5 x^{2} - 36 x - 81

\frac{x}{4} = \frac{7}{12}

\frac{1}{9 ^{- 2}}

28 x^{3} - 63 x

What are the solutions to the equation 4x^2-12x=7 ?
The solutions to the equation 4x^2-12x=7 are x= 7/2 ,x=-1/2
Find the zeros of 4x^2-12x=7
The zeros of 4x^2-12x=7 are x= 7/2 ,x=-1/2