What are the solutions to the equation (3x+2)^2-12=0 ?

The solutions to the equation (3x+2)^2-12=0 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3

Find the zeros of (3x+2)^2-12=0

The zeros of (3x+2)^2-12=0 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3

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(3 x + 2)^{2} - 12 = 0

x = \frac{2 3 - 2}{3}, x = \frac{- 2 3 - 2}{3}

Decimal Notation

x = 0.48803 \dots, x = - 1.82136 \dots

Solution steps

(3 x + 2)^{2} - 12 = 0

Move

12

to the right side

(3 x + 2)^{2} = 12

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 x + 2 = 12 : x = \frac{2 3 - 2}{3}

Solve

3 x + 2 = - 12 : x = \frac{- 2 3 - 2}{3}

The solutions to the quadratic equation are:

x = \frac{2 3 - 2}{3}, x = \frac{- 2 3 - 2}{3}

(\frac{20 !}{1 ! ( 20 - 1 ) !}) (0.98)^{19} (0.02)

2 \cdot 3^{- 1}

ln (16) - ln (8)

24 x^{2} y + 18 x y^{2} - 2 y

3 ∣ x - 7 ∣ + 6 = 9

What are the solutions to the equation (3x+2)^2-12=0 ?
The solutions to the equation (3x+2)^2-12=0 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3
Find the zeros of (3x+2)^2-12=0
The zeros of (3x+2)^2-12=0 are x=(2sqrt(3)-2)/3 ,x=(-2sqrt(3)-2)/3