What are the solutions to the equation -4(x-2)^2-3=0 ?

The solutions to the equation -4(x-2)^2-3=0 are x=2+i(sqrt(3))/2 ,x=2-i(sqrt(3))/2

Find the zeros of -4(x-2)^2-3=0

The zeros of -4(x-2)^2-3=0 are x=2+i(sqrt(3))/2 ,x=2-i(sqrt(3))/2

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- 4 (x - 2)^{2} - 3 = 0

x = 2 + i \frac{3}{2}, x = 2 - i \frac{3}{2}

Solution steps

- 4 (x - 2)^{2} - 3 = 0

Move

3

to the right side

- 4 (x - 2)^{2} = 3

Divide both sides by

- 4

(x - 2)^{2} = - \frac{3}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 2 = - \frac{3}{4} : x = 2 + i \frac{3}{2}

Solve

x - 2 = - - \frac{3}{4} : x = 2 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = 2 + i \frac{3}{2}, x = 2 - i \frac{3}{2}

(7^{2})^{6}

(4 s^{4})^{\frac{1}{2}}

8 x + 10

2 x + 9 = x + 4

x^{2} + 5 x + 4

What are the solutions to the equation -4(x-2)^2-3=0 ?
The solutions to the equation -4(x-2)^2-3=0 are x=2+i(sqrt(3))/2 ,x=2-i(sqrt(3))/2
Find the zeros of -4(x-2)^2-3=0
The zeros of -4(x-2)^2-3=0 are x=2+i(sqrt(3))/2 ,x=2-i(sqrt(3))/2