What are the solutions to the equation -x^2+5x+2=0 ?

The solutions to the equation -x^2+5x+2=0 are x=-(-5+sqrt(33))/2 ,x=(5+sqrt(33))/2

Find the zeros of -x^2+5x+2=0

The zeros of -x^2+5x+2=0 are x=-(-5+sqrt(33))/2 ,x=(5+sqrt(33))/2

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- x^{2} + 5 x + 2 = 0

x = - \frac{- 5 + 33}{2}, x = \frac{5 + 33}{2}

Decimal Notation

x = - 0.37228 \dots, x = 5.37228 \dots

Solution steps

- x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) \cdot 2}{2 ( - 1 )}

5^{2} - 4 (- 1) \cdot 2 = 33

x_{1, 2} = \frac{- 5 \pm 33}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 33}{2 ( - 1 )}, x_{2} = \frac{- 5 - 33}{2 ( - 1 )}

x = \frac{- 5 + 33}{2 ( - 1 )} : - \frac{- 5 + 33}{2}

x = \frac{- 5 - 33}{2 ( - 1 )} : \frac{5 + 33}{2}

The solutions to the quadratic equation are:

x = - \frac{- 5 + 33}{2}, x = \frac{5 + 33}{2}

lo g_{2} (128)

22 y = 18 (y - 2)

1936

3 (x - 1) = 6

4 x + 6 + 3 = 17

What are the solutions to the equation -x^2+5x+2=0 ?
The solutions to the equation -x^2+5x+2=0 are x=-(-5+sqrt(33))/2 ,x=(5+sqrt(33))/2
Find the zeros of -x^2+5x+2=0
The zeros of -x^2+5x+2=0 are x=-(-5+sqrt(33))/2 ,x=(5+sqrt(33))/2