What are the solutions to the equation (8m+12)^2=4 ?

The solutions to the equation (8m+12)^2=4 are m=-5/4 ,m=-7/4

Find the zeros of (8m+12)^2=4

The zeros of (8m+12)^2=4 are m=-5/4 ,m=-7/4

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(8 m + 12)^{2} = 4

m = - \frac{5}{4}, m = - \frac{7}{4}

Decimal Notation

m = - 1.25, m = - 1.75

Solution steps

(8 m + 12)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

8 m + 12 = 4 : m = - \frac{5}{4}

Solve

8 m + 12 = - 4 : m = - \frac{7}{4}

The solutions to the quadratic equation are:

m = - \frac{5}{4}, m = - \frac{7}{4}

0 = 2 x^{2} + 5 x + 6

x^{2} + 80 = - 16 x

\frac{2 3}{12}

m^{8} - n^{8}

(8 \frac{2}{3})^{4}

What are the solutions to the equation (8m+12)^2=4 ?
The solutions to the equation (8m+12)^2=4 are m=-5/4 ,m=-7/4
Find the zeros of (8m+12)^2=4
The zeros of (8m+12)^2=4 are m=-5/4 ,m=-7/4