What are the solutions to the equation t^2+3/2 t-2/3 =0 ?

The solutions to the equation t^2+3/2 t-2/3 =0 are t=(-9+sqrt(177))/(12),t=(-9-sqrt(177))/(12)

Find the zeros of t^2+3/2 t-2/3 =0

The zeros of t^2+3/2 t-2/3 =0 are t=(-9+sqrt(177))/(12),t=(-9-sqrt(177))/(12)

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t^{2} + \frac{3}{2} t - \frac{2}{3} = 0

t = \frac{- 9 + 177}{12}, t = \frac{- 9 - 177}{12}

Decimal Notation

t = 0.35867 \dots, t = - 1.85867 \dots

Solution steps

t^{2} + \frac{3}{2} t - \frac{2}{3} = 0

Find Least Common Multiplier of

2, 3 : 6

Multiply by LCM=

6

t^{2} \cdot 6 + \frac{3}{2} t \cdot 6 - \frac{2}{3} \cdot 6 = 0 \cdot 6

Simplify

6 t^{2} + 9 t - 4 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

9^{2} - 4 \cdot 6 (- 4) = 177

t_{1, 2} = \frac{- 9 \pm 177}{2 \cdot 6}

Separate the solutions

t_{1} = \frac{- 9 + 177}{2 \cdot 6}, t_{2} = \frac{- 9 - 177}{2 \cdot 6}

t = \frac{- 9 + 177}{2 \cdot 6} : \frac{- 9 + 177}{12}

t = \frac{- 9 - 177}{2 \cdot 6} : \frac{- 9 - 177}{12}

The solutions to the quadratic equation are:

t = \frac{- 9 + 177}{12}, t = \frac{- 9 - 177}{12}

76 \cdot 1 0^{- 12} s^{2} + 30 \cdot 1 0^{- 4} s + 820 = 0

ab + 2 a + 3 b + 6

\frac{1}{4} x^{2} - 1 = 15

\frac{n - 5}{2} = 5

3^{0} + 2^{0}

What are the solutions to the equation t^2+3/2 t-2/3 =0 ?
The solutions to the equation t^2+3/2 t-2/3 =0 are t=(-9+sqrt(177))/(12),t=(-9-sqrt(177))/(12)
Find the zeros of t^2+3/2 t-2/3 =0
The zeros of t^2+3/2 t-2/3 =0 are t=(-9+sqrt(177))/(12),t=(-9-sqrt(177))/(12)