What are the solutions to the equation x^2-5x+1=1 ?

The solutions to the equation x^2-5x+1=1 are x=5,x=0

Find the zeros of x^2-5x+1=1

The zeros of x^2-5x+1=1 are x=5,x=0

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x^{2} - 5 x + 1 = 1

x = 5, x = 0

Solution steps

x^{2} - 5 x + 1 = 1

Move

1

to the left side

x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

x = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 5, x = 0

0 = r + 4

y^{2} - 3 y - 5 = 0

f (y) = 0.5 y - 1 - (2 y + 4)

(x + 3)^{2} = - 4

15 x^{3} y^{5} - 25 x^{4} y^{2} + 10 x^{6} y^{4}

What are the solutions to the equation x^2-5x+1=1 ?
The solutions to the equation x^2-5x+1=1 are x=5,x=0
Find the zeros of x^2-5x+1=1
The zeros of x^2-5x+1=1 are x=5,x=0