What is the answer to x^2-9=(x+3)(x-3) ?

The answer to x^2-9=(x+3)(x-3) is True for all x

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x^2-9=(x+3)(x-3)

x^{2} - 9 = (x + 3) (x - 3)

True for all x

Solution steps

x^{2} - 9 = (x + 3) (x - 3)

Expand

(x + 3) (x - 3) : x^{2} - 9

x^{2} - 9 = x^{2} - 9

Move

9

to the right side

x^{2} = x^{2}

Move

x^{2}

to the left side

0 = 0

Both sides are equal

True for all x

x^{3} - 2 x^{2} - 3 x

3 x^{2} + x + 1 = 0

2 x = 5 x

2 x^{3} + x^{2} - 32 x - 16

∣ x - 6 ∣ = 14

What is the answer to x^2-9=(x+3)(x-3) ?
The answer to x^2-9=(x+3)(x-3) is True for all x
Solve for x: x^2-9=(x+3)(x-3)
The solution is True for all x