What are the solutions to the equation 3x^2-x-5=0 ?

The solutions to the equation 3x^2-x-5=0 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6

Find the zeros of 3x^2-x-5=0

The zeros of 3x^2-x-5=0 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6

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3 x^{2} - x - 5 = 0

x = \frac{1 + 61}{6}, x = \frac{1 - 61}{6}

Decimal Notation

x = 1.46837 \dots, x = - 1.13504 \dots

Solution steps

3 x^{2} - x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 5 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 5) = 61

x_{1, 2} = \frac{- ( - 1 ) \pm 61}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 61}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 61}{2 \cdot 3}

x = \frac{- ( - 1 ) + 61}{2 \cdot 3} : \frac{1 + 61}{6}

x = \frac{- ( - 1 ) - 61}{2 \cdot 3} : \frac{1 - 61}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 61}{6}, x = \frac{1 - 61}{6}

1 = 3 (x - 4)

x^{2} + 14 x - 32

x^{2} - 10 x = - 35

\frac{2}{3} t = \frac{5}{2}

1 6^{2} + 1 6^{2}

What are the solutions to the equation 3x^2-x-5=0 ?
The solutions to the equation 3x^2-x-5=0 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6
Find the zeros of 3x^2-x-5=0
The zeros of 3x^2-x-5=0 are x=(1+sqrt(61))/6 ,x=(1-sqrt(61))/6