What are the solutions to the equation (4x+5)^2=5x^2+4x ?

The solutions to the equation (4x+5)^2=5x^2+4x are x=-1,x=-25/11

Find the zeros of (4x+5)^2=5x^2+4x

The zeros of (4x+5)^2=5x^2+4x are x=-1,x=-25/11

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(4 x + 5)^{2} = 5 x^{2} + 4 x

x = - 1, x = - \frac{25}{11}

Decimal Notation

x = - 1, x = - 2.27272 \dots

Solution steps

(4 x + 5)^{2} = 5 x^{2} + 4 x

Expand

(4 x + 5)^{2} : 16 x^{2} + 40 x + 25

16 x^{2} + 40 x + 25 = 5 x^{2} + 4 x

Move

4 x

to the left side

16 x^{2} + 36 x + 25 = 5 x^{2}

Move

5 x^{2}

to the left side

11 x^{2} + 36 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 11 \cdot 25}{2 \cdot 11}

3 6^{2} - 4 \cdot 11 \cdot 25 = 14

x_{1, 2} = \frac{- 36 \pm 14}{2 \cdot 11}

Separate the solutions

x_{1} = \frac{- 36 + 14}{2 \cdot 11}, x_{2} = \frac{- 36 - 14}{2 \cdot 11}

x = \frac{- 36 + 14}{2 \cdot 11} : - 1

x = \frac{- 36 - 14}{2 \cdot 11} : - \frac{25}{11}

The solutions to the quadratic equation are:

x = - 1, x = - \frac{25}{11}

lo g_{3} (x) = 2

32 - \frac{64}{3} + \frac{32}{5}

m^{2} - 6 m + 5

x^{2} + x < 0

\frac{9 x ^{3} y ^{8}}{45 x ^{2} y ^{6}}

What are the solutions to the equation (4x+5)^2=5x^2+4x ?
The solutions to the equation (4x+5)^2=5x^2+4x are x=-1,x=-25/11
Find the zeros of (4x+5)^2=5x^2+4x
The zeros of (4x+5)^2=5x^2+4x are x=-1,x=-25/11