What are the solutions to the equation x^2=12x-52 ?

The solutions to the equation x^2=12x-52 are x=6+4i,x=6-4i

Find the zeros of x^2=12x-52

The zeros of x^2=12x-52 are x=6+4i,x=6-4i

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x^{2} = 12 x - 52

x = 6 + 4 i, x = 6 - 4 i

Solution steps

x^{2} = 12 x - 52

Move

52

to the left side

x^{2} + 52 = 12 x

Move

12 x

to the left side

x^{2} + 52 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 12 x + 52 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot 52}{2 \cdot 1}

Simplify

(- 12)^{2} - 4 \cdot 1 \cdot 52 : 8 i

x_{1, 2} = \frac{- ( - 12 ) \pm 8 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8 i}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 8 i}{2 \cdot 1}

x = \frac{- ( - 12 ) + 8 i}{2 \cdot 1} : 6 + 4 i

x = \frac{- ( - 12 ) - 8 i}{2 \cdot 1} : 6 - 4 i

The solutions to the quadratic equation are:

x = 6 + 4 i, x = 6 - 4 i

x^{2} + 11 x + 30 \geq 0

∣ 4 - x ∣ = 2 x + 1

24 x^{3} - 81 y^{3}

(\frac{3}{4})^{4}

25 x^{2} - 10 x - 24

What are the solutions to the equation x^2=12x-52 ?
The solutions to the equation x^2=12x-52 are x=6+4i,x=6-4i
Find the zeros of x^2=12x-52
The zeros of x^2=12x-52 are x=6+4i,x=6-4i