What are the solutions to the equation 3x^2+5x-12=0 ?

The solutions to the equation 3x^2+5x-12=0 are x= 4/3 ,x=-3

Find the zeros of 3x^2+5x-12=0

The zeros of 3x^2+5x-12=0 are x= 4/3 ,x=-3

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3 x^{2} + 5 x - 12 = 0

x = \frac{4}{3}, x = - 3

Solution steps

3 x^{2} + 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 3 ( - 12 )}{2 \cdot 3}

5^{2} - 4 \cdot 3 (- 12) = 13

x_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 5 + 13}{2 \cdot 3}, x_{2} = \frac{- 5 - 13}{2 \cdot 3}

x = \frac{- 5 + 13}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 5 - 13}{2 \cdot 3} : - 3

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 3

\frac{2 π}{\frac{π}{2}}

8 y^{3} - 125 y^{6}

∣ 4 x - 5 ∣ = ∣ 9 - 4 x ∣

2^{l o g_{2} (n)}

3 p^{2} - 2 p - 5

What are the solutions to the equation 3x^2+5x-12=0 ?
The solutions to the equation 3x^2+5x-12=0 are x= 4/3 ,x=-3
Find the zeros of 3x^2+5x-12=0
The zeros of 3x^2+5x-12=0 are x= 4/3 ,x=-3