What are the solutions to the equation 3x^2-12x=9 ?

The solutions to the equation 3x^2-12x=9 are x=2+sqrt(7),x=2-sqrt(7)

Find the zeros of 3x^2-12x=9

The zeros of 3x^2-12x=9 are x=2+sqrt(7),x=2-sqrt(7)

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3 x^{2} - 12 x = 9

x = 2 + 7, x = 2 - 7

Decimal Notation

x = 4.64575 \dots, x = - 0.64575 \dots

Solution steps

3 x^{2} - 12 x = 9

Move

9

to the left side

3 x^{2} - 12 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 9) = 67

x_{1, 2} = \frac{- ( - 12 ) \pm 6 7}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 6 7}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 6 7}{2 \cdot 3}

x = \frac{- ( - 12 ) + 6 7}{2 \cdot 3} : 2 + 7

x = \frac{- ( - 12 ) - 6 7}{2 \cdot 3} : 2 - 7

The solutions to the quadratic equation are:

x = 2 + 7, x = 2 - 7

- 3 c + 15 = 3

\frac{( a + b ) ^{9}}{( a + b ) ^{4}}

\frac{x}{2} \leq \frac{5}{8}

5 x^{3} + 15 x^{2} - 2 x - 6

3 x - 8 = x + 2

What are the solutions to the equation 3x^2-12x=9 ?
The solutions to the equation 3x^2-12x=9 are x=2+sqrt(7),x=2-sqrt(7)
Find the zeros of 3x^2-12x=9
The zeros of 3x^2-12x=9 are x=2+sqrt(7),x=2-sqrt(7)