What are the solutions to the equation 4x-x^2=3 ?

The solutions to the equation 4x-x^2=3 are x=1,x=3

Find the zeros of 4x-x^2=3

The zeros of 4x-x^2=3 are x=1,x=3

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4 x - x^{2} = 3

x = 1, x = 3

Solution steps

4 x - x^{2} = 3

Move

3

to the left side

4 x - x^{2} - 3 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

4^{2} - 4 (- 1) (- 3) = 2

x_{1, 2} = \frac{- 4 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2}{2 ( - 1 )}

x = \frac{- 4 + 2}{2 ( - 1 )} : 1

x = \frac{- 4 - 2}{2 ( - 1 )} : 3

The solutions to the quadratic equation are:

x = 1, x = 3

945 - 75

\frac{1}{4} - \frac{1}{12}

\frac{9 !}{( 9 - 4 ) !}

2 x^{2} + 3 = 5 x + 6

\frac{( 3 - 5 X )}{2} < \frac{( 2 X - 8 )}{4} < X - 3

What are the solutions to the equation 4x-x^2=3 ?
The solutions to the equation 4x-x^2=3 are x=1,x=3
Find the zeros of 4x-x^2=3
The zeros of 4x-x^2=3 are x=1,x=3