What are the solutions to the equation -1/12 x^2+6x+3=0 ?

The solutions to the equation -1/12 x^2+6x+3=0 are x=-6(sqrt(37)-6),x=6(6+sqrt(37))

Find the zeros of -1/12 x^2+6x+3=0

The zeros of -1/12 x^2+6x+3=0 are x=-6(sqrt(37)-6),x=6(6+sqrt(37))

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- \frac{1}{12} x^{2} + 6 x + 3 = 0

x = - 6 (37 - 6), x = 6 (6 + 37)

Solution steps

- \frac{1}{12} x^{2} + 6 x + 3 = 0

Multiply both sides by

12

- x^{2} + 72 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 ( - 1 ) \cdot 36}{2 ( - 1 )}

7 2^{2} - 4 (- 1) \cdot 36 = 1237

x_{1, 2} = \frac{- 72 \pm 12 37}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 72 + 12 37}{2 ( - 1 )}, x_{2} = \frac{- 72 - 12 37}{2 ( - 1 )}

x = \frac{- 72 + 12 37}{2 ( - 1 )} : - 6 (37 - 6)

x = \frac{- 72 - 12 37}{2 ( - 1 )} : 6 (6 + 37)

The solutions to the quadratic equation are:

x = - 6 (37 - 6), x = 6 (6 + 37)

x - 4 \geq - 11

10 > - 2 x + 4 > - 4

p = ln (2) + ln (5 + 1)

- \frac{6}{5} - 1

\frac{2}{3} - 1

What are the solutions to the equation -1/12 x^2+6x+3=0 ?
The solutions to the equation -1/12 x^2+6x+3=0 are x=-6(sqrt(37)-6),x=6(6+sqrt(37))
Find the zeros of -1/12 x^2+6x+3=0
The zeros of -1/12 x^2+6x+3=0 are x=-6(sqrt(37)-6),x=6(6+sqrt(37))