What are the solutions to the equation 3x^2-6x+25=0 ?

The solutions to the equation 3x^2-6x+25=0 are x=1+isqrt(22/3),x=1-isqrt(22/3)

Find the zeros of 3x^2-6x+25=0

The zeros of 3x^2-6x+25=0 are x=1+isqrt(22/3),x=1-isqrt(22/3)

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3 x^{2} - 6 x + 25 = 0

x = 1 + i \frac{22}{3}, x = 1 - i \frac{22}{3}

Solution steps

3 x^{2} - 6 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 25}{2 \cdot 3}

Simplify

(- 6)^{2} - 4 \cdot 3 \cdot 25 : 266 i

x_{1, 2} = \frac{- ( - 6 ) \pm 2 66 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 66 i}{2 \cdot 3}, x_{2} = \frac{- ( - 6 ) - 2 66 i}{2 \cdot 3}

x = \frac{- ( - 6 ) + 2 66 i}{2 \cdot 3} : 1 + i \frac{22}{3}

x = \frac{- ( - 6 ) - 2 66 i}{2 \cdot 3} : 1 - i \frac{22}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{22}{3}, x = 1 - i \frac{22}{3}

\frac{1}{2} (3)^{2}

\frac{x ^{2} + 7 x}{x - 4} > 0

\frac{1 - 4 ( 4 )}{15}

- x^{2} + x + 6 \geq 0

lo g_{8} (4) + lo g_{8} (16)

What are the solutions to the equation 3x^2-6x+25=0 ?
The solutions to the equation 3x^2-6x+25=0 are x=1+isqrt(22/3),x=1-isqrt(22/3)
Find the zeros of 3x^2-6x+25=0
The zeros of 3x^2-6x+25=0 are x=1+isqrt(22/3),x=1-isqrt(22/3)